Re: Strings: how to check for non-numeric chars..

From:

"Andrew Thompson" <u32984@uwe>

Newsgroups:

comp.lang.java.help

Date:

Sun, 11 Nov 2007 08:17:02 GMT

Message-ID:

<7b0b56f30206e@uwe>

maya wrote:
...

I can't figure out to check whether or not a string contains any
non-numeric characters (to 'pass' my filter it can only contain chars
from 1 to 9, that's it...

What about 0?

<sscce>
class TestDigits {

  public static Integer parseAsInt(String s) {
    return Integer.parseInt( s );
  }

  public static boolean isAllDigits(String s) {
    for (int ii=0; ii<s.length(); ii++) {
      char currentChar = s.charAt(ii);
      //Character currentCharacter = new Character(currentChar);
      System.out.println(
        currentChar +
        " is digit: " +
        Character.isDigit( currentChar ) );
      if ( !Character.isDigit( currentChar ) ) {
        return false;
      }
    }
    return true;
  }

  public static void main(String[] args) {
    String test = "615";
    System.out.println( test +
      " is all digits: " +
      isAllDigits(test) );
    System.out.println( test +
      " parses as Integer: " +
      parseAsInt(test) );

    test = "-1";
    System.out.println( test +
      " is all digits: " +
      isAllDigits( test ) );
    System.out.println( test +
      " parses as Integer: " +
      parseAsInt(test) );

    test = "615.0";
    System.out.println( test +
      " is all digits: " +
      isAllDigits( test ) );
    System.out.println( test +
      " parses as Integer: " +
      parseAsInt(test) );
  }
}
</sscce>

--
Andrew Thompson
http://www.athompson.info/andrew/

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