Re: How associate two HashMaps

From:
Lew <lewbloch@gmail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Tue, 8 May 2012 09:27:58 -0700 (PDT)
Message-ID:
<11781872.127.1336494478259.JavaMail.geo-discussion-forums@pbqn10>
javax.swing.JSnarker wrote:

Stefan Ram wrote:

Ricardo Nuno writes:

What do I need to associate a value, from one hashMap to a key from a
new HashMap


   It is hard to parse this sentence with the comma.

   =BBTo associate a value to a key=AB is a little bit vague.

 
My guess is that he wants a bidirectional map. For that you'd need a
custom class delegating to two internal HashMap instances. Something like
 
public class BidiMap<K,V> extends AbstractMap<K,V> {


In Apache Commons Collections 'BidiMap' is an interface with a double handf=
ul
of implementing classes:
<http://commons.apache.org/collections/api-release/org/apache/commons/colle=
ctions/BidiMap.html>

     private Map<K,V> map1, map2;
     private BidiMap<V,K> reversed;
 
     public BidiMap () {
         map1 = new HashMap<K,V>();
         map2 = new HashMap<K,V>();
         reversed = new BidiMap<K,V>(map2, map1, this);
     }
 
     private BidiMap (Map<K,V> map1, Map<K,V> map2, BidiMap<V,K> reversed=

) {

         this.map1 = map1; this.map2 = map2; this.reversed = revers=

ed;

     }
 
     private BidiMap<V,K> getReversedMap () {
         return reversed;
     }
 
     /* Map methods go here. View methods delegate to map1. Modifying
        methods operate on both maps, but reverse key and value when
        modifying map2. Also, if a value is already in map2, looks
        it up in map2 to find the corresponding key and removes
        that key from map1 before adding the new mappings to both maps.
     */
}
 
Changes to the reversed map will be reflected in the original and vice
versa.


JSnarker's example is a good one for understanding the mechanics of the
bidirectional map. The Apache Commons libraries are the go-to source for
most convenience types not in the standard API.

If you need a different kind of association, well, there are all kinds of w=
ays
to do that, as Stefan pointed out.

Another possibility is that you're looking for a way to associate more than=
 one value with the same key. There are a number of ways to do that:

Here's one (not tried or even compiled here, so might need tweaking):

public interface Pair<L, R>
{
  L getLeft();
  R getRight();
}

public class BasePair<L, R> implements Pair<L, R>
{
  private final L left;
  private final R right;
  public BasePair(L left, R right)
  {
    this.left = left;
    this.right = right;
  }

  public L getLeft() { return left; }
  public R getRight() { return right; }
}

public class MultiAssociator<K, L, R>
{
  private final Map<K, Pair<L, R>> associator = new HashMap<>();

  public Pair<L, R> put(K key, Pair<L, R> pair)
  {
    if (key == null || pair == null)
    {
      throw new IllegalArgumentException("Argument cannot be null");
    }
    return associator.put(key, pair);
  }

  public Pair<L, R> put(K key, L left, R right)
  {
    return associator.put(key, new Pair<>(left, right));
  }

  public Pair<L, R> put(K key, L left)
  {
    if (key == null)
    {
      throw new IllegalArgumentException("Argument cannot be null");
    }
    Pair<L, R> value = associator.get(key);
    Pair<L, R> repla = value == null? new Pair<>(left, null)
                : new Pair<>(left, value.getRight());
    return associator.put(key, repla);
  }

  public Pair<L, R> put(K key, R right)
  {
    if (key == null)
    {
      throw new IllegalArgumentException("Argument cannot be null");
    }
    Pair<L, R> value = associator.get(key);
    Pair<L, R> repla = value == null? new Pair(null, right)
                : new Pair(value.getLeft(), right);
    return associator.put(key, repla);
  }

  public Pair<L, R> get(K key)
  {
    return associator.get(key);
  }
}

--
Lew

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