Re: Reporting tool in Java

From:
ram@zedat.fu-berlin.de (Stefan Ram)
Newsgroups:
comp.lang.java.programmer
Date:
7 Feb 2007 10:35:26 GMT
Message-ID:
<template-20070207113135@ram.dialup.fu-berlin.de>
"Jujo" <iuio@wp.pl> writes:

Does anyone know a reporting tool in Java, which can load a
template (previously made in Word or other word processor, for
example) and fill in defined fields ? (inside the report are
some sophisticated features which cannot be achieved with
iReport + JasperReport)


  With Microsoft? Word installed, one can use a COM brigde to
  open Microsoft? Word and control it from within a Java
  program to instantiate and print the template.

  This way, one does not have to write Java code to parse and
  interpret Microsoft? Word files.

  Otherwise, in order to instantiate a custom template (not a
  Microsoft? Word template) in Java one does not need a library
  for simple cases.

public class Main
{
  public static java.lang.String replace
  ( final java.lang.String template,
    final java.util.Map<java.lang.String,java.lang.String> map )
  { final java.lang.StringBuilder list =
    new java.lang.StringBuilder( "\\$(" );
    for( final java.lang.String key: map.keySet() )
    { list.append( key ); list.append( "|" ); }
    list.append( "[^\\s\\S])" );
    java.util.regex.Pattern pattern =
    java.util.regex.Pattern.compile( list.toString() );
    java.util.regex.Matcher matcher = pattern.matcher( template );
    final java.lang.StringBuffer stringBuffer = new java.lang.StringBuffer();
    while( matcher.find() )
    { final java.lang.String string = matcher.group( 1 );
      matcher.appendReplacement
      ( stringBuffer, map.get( string )); }
    matcher.appendTail( stringBuffer );
    return stringBuffer.toString(); }

  public static void main( final java.lang.String[] args )
  { final java.util.Map<java.lang.String,java.lang.String> map =
    new java.util.HashMap<java.lang.String,java.lang.String>();
    map.put( "user", "Mary" );
    map.put( "name", "Patricia" );
    java.lang.System.out.println
    ( replace( "Hello $user, my name is $name.", map ) ); }}

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