Re: How do I do this?

From:
"tim@nocomment.com" <tbil99@netscape.net>
Newsgroups:
comp.lang.java.programmer
Date:
10 Feb 2007 05:57:08 -0800
Message-ID:
<1171115828.838743.55950@h3g2000cwc.googlegroups.com>
On Feb 10, 3:08 am, "Mike Schilling" <mscottschill...@hotmail.com>
wrote:

"t...@nocomment.com" <tbi...@netscape.net> wrote in message

news:1171094182.389622.95280@a34g2000cwb.googlegroups.com...

I am trying to use an array of some sort which will allow me to access
a value based on a key (like in a Hashtable) but also allow me to
access all entries sorted by the key.
I have heard all kinds of solutions proposed but there seems to be
nothing as straight forward as there should be.
Can anyone give me some sample code where the table or tree or
whatever is accessed by both the key and iterated through in key
order?


Look at java.util.TreeMap.


How do you iterate through the TreeMap. So far, I have this but I am
not sure how to loop through the map and get all of the keys and
values.

package test;

import java.util.*;

public class HashtableToVector {
    public static void main (String[] args)
    {
      Collection c;
      Iterator iter;

      TreeMap map = new TreeMap ();
      map.put ("ccc", "third.6");
      map.put ("bb3", "second.3");
      map.put ("bb2", "second.2");
      map.put ("bb1", "second.1");
      map.put ("aaa", "third");

      System.out.println ("map = " + map);
      System.out.println ("map.get('bb3') = " + map.get("bb3"));
    }
}

And I get as output
:
map = {aaa=third, bb1=second.1, bb2=second.2, bb3=second.3, ccc=third.
6}
map.get('bb3') = second.3

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