Re: [List handling][Resolved]number of occurences

From:
Daniel Moyne <dmoyne@tiscali.fr>
Newsgroups:
comp.lang.java.help
Date:
Tue, 07 Aug 2007 14:51:43 +0200
Message-ID:
<f99pst$p4k$1@news.tiscali.fr>
Daniel Moyne wrote:

Andrew Thompson wrote:

Daniel Moyne wrote:

I have this type of list :


Yeh.. good or you. Did you have any form of *question*
based upon an *SSCCE* that anybody might give more
than a passing stuff about?

(I'm saying this, with vague irritation for the fact the OP
has asked other questions on this forum that developed
into complex and disparate threads to which the OP did
not reply)

So ..be warned D.M. try to get more active in the replies to
the threads *you* start, or expect much shorter, and more terse
replies from *me*, in future.

This in *not* a help desk, in case you night have any
misaprehensions.

Andrew,
what do *SSCCE* and OP stand for ?

Java code of runable example is herewith provided :
import java.util.Map;
import java.util.HashMap;
import java.util.TreeMap;

public class SortStringWithOccurenceCount {

public static void main (String args []) {
 
String[]allStrings={"jean","pierre","jean","michel","louis","louis","pierre","philippe","jean"};
  Map<String,Integer>myStrings= new HashMap<String, Integer>();
  /* we build the HashMap with no need for any sorting during this
procedures */
  /* key=String value= number of occurence */
  for (int i=0;i<allStrings.length;i++) {
    String ff=allStrings[i];
    if (!myStrings.containsKey(ff)) {
      myStrings.put(ff,1);
    }
    else {
      myStrings.put(ff,myStrings.get(ff)+1);
    }
  }
  /* we sort the map by alphabetical order of string key */
  myStrings=new TreeMap<String,Integer>(myStrings);
  /* we list result of search */
  for (Map.Entry <String,Integer> entry :myStrings.entrySet()) {
    String aa=entry.getKey();
      int ii=entry.getValue();
      System.out.println("STRING = "+aa+" VALUE = "+Integer.toString(ii));
    }
  }
}

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