Re: Doubt regarding "Protected" access specifier across different packages

From:

Lew <lew@lewscanon.com>

Newsgroups:

comp.lang.java.programmer

Date:

Mon, 24 Sep 2007 01:20:43 -0400

Message-ID:

<CZKdnZ6_eqmx1GrbnZ2dnUVZ_tqtnZ2d@comcast.com>

sayantan wrote:

Hi Roedy,

I went through the link you provided.It's written that the "protected"
is visible to classes outside the package that inherit the class.
And this is my exact point of confusion as I should not get these
errors accroding to this rule.

Please do not top-post.

This was answered earlier. Read:
<http://java.sun.com/docs/books/jls/third_edition/html/names.html#6.6.2.2>

As I mentioned:

You can use a constructor for the object itself, inheriting the constructor,
but not for another object, where inheritance isn't involved.

In other words, the protected constructor can only be used by the object
itself, i.e., through an implicit or explicit super() call (or other
constructor). You were calling the constructor of an object other than this.
That is forbidden.

It is not enough that the invoking object be of the child class. It must also
be constructing itself.

Did you have difficulty with this answer before? What is the part that gives
you trouble?

--
Lew