Re: errors in Hashtable to HashMap

From:
"Matt Humphrey" <matth@iviz.com>
Newsgroups:
comp.lang.java.help
Date:
Fri, 2 May 2008 09:24:27 -0400
Message-ID:
<p--dnTsr1eGNi4bVnZ2dnUVZ_sednZ2d@comcast.com>
"bH" <bherbst65@hotmail.com> wrote in message
news:589c4c74-81c5-4e28-a36e-a18cf975064d@l42g2000hsc.googlegroups.com...

Hi All,

This is a scaled down version of the program:
http://sio.midco.net/dfranklin/phonedial/index.html


<snip prelude>

import java.applet.*;
import java.awt.*;
import java.util.HashMap;

public class TestPhneDialer extends Applet {
 boolean DEBUG = false;
 HashMap buttonSoundNames;

^^^ You declare instance var. buttonSoundNames here, value is null

 KeyPad keyPad;

 public void init() {
   keyPad = new KeyPad();
   HashMap<Button,String>buttonSoundNames =
new HashMap<Button,String>(3,3);

^^^ You create a local variable buttonSoundNames here, initialize it and
insert values. But it is totally separate to the instance variable. Drop
the declaration part.

   buttonSoundNames.put(keyPad.b1, "1.au");
   buttonSoundNames.put(keyPad.b2, "2.au");
   buttonSoundNames.put(keyPad.b3, "3.au");
   setLayout(new FlowLayout());
   add(keyPad);
   validate();
   System.out.println("Test line 1");
   String btn3 = buttonSoundNames.get(keyPad.b3);
   // will show "3.au"
   System.out.println(btn3);
 }

 public boolean action(Event e, Object arg) {
   if (e.target instanceof Button) {
     System.out.println("Test line 2");
     String name = new String((String)
buttonSoundNames.get((Button)e.target));

^^^ You use the instance variable here, but it's value is null still.
Also, the new String() and casts are superfluous. Just say
String name = buttonSoundNames.get(e.target). You may find it clearer to
keep the Button cast--I'm not sure which will be more readable.

Matt Humphrey http://www.iviz.com/

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