Re: Perl Pro but Java Newbie: Need nudge in proper direction for my favorite Perl routine in Java

From:
"/usr/ceo" <newsbot@cox.net>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 14 Sep 2008 16:03:38 -0700 (PDT)
Message-ID:
<bf2cc93f-bbda-4bc3-983e-f9a3c2110e37@m3g2000hsc.googlegroups.com>
On Sep 14, 5:23 pm, Mark Space <marksp...@sbcglobal.net> wrote:

/usr/ceo wrote:

It's not just Java, but all languages that don't allow instring
substitution that I've never really liked. It drives me buts to have


OK, re-read this and had a thought. What is "in-string substitution"?
You mean like printf?

Geeze, if that's what you wanted, you should have asked:

<http://java.sun.com/j2se/1.5.0/docs/api/java/util/Formatter.html>

    // Writes a formatted string to System.out.

    System.out.format("Local time: %tT", Calendar.getInstance());
    // -> "Local time: 13:34:18"

    // Writes formatted output to System.err.

    System.err.printf("Unable to open file '%1$s': %2$s",
                      fileName, exception.getMessag=

e());

    // -> "Unable to open file 'food': No such file or directory"


Instring substitution meaning this:

Ruby:

what="dog"
puts "The #{what} days of summer"

Perl:

$what = 'dog';
print "The $what days of summer\n";

Also known as string interpolation. Love it. Taking an example
someone else left where they spoke rather convincingly that I was
merely substituting commas (,) for pluses (+):

class TestOut {
   public static void main ( Strings ... args ) {
     int i = 5;
     Object o = new Object();
     javax.swing.JLabel label = new javax.swing.JLabel( "Hi" );
     System.out.println( "I have " + i + " ints and I have " +
                         "\nthis " + o + " thing here and " +
                         "\nI have a JLabel " + label + "." +
                         "\nHave a nice day!"
         );
   }

}

Perl:

#!/usr/bin/perl
$|++;

use strict;
use warnings qw( all );
use MyOrg::SimpleObject;

my $int = 5;
my $dog = "Fido";
my $o = MyOrg::SimpleObject->new( name => 'Java Crammer' );
$o->name( '/usr/ceo' );

print "I have an int as $int, and my dog's name is $dog, and my name
is ${\ $o->name }...\n";

I have an int as 5, and my dog's name is Fido, and my name is /usr/ceo.=

...

Like that... Not using format or printf... I don't expect to be able
to do this in Java. That's fine.

/usr/ceo

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