Re: Hashcode and Equal

From:
Roedy Green <see_website@mindprod.com.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Tue, 09 Mar 2010 03:44:47 -0800
Message-ID:
<43dcp5tcce8n02pigvnuu2vqjat1s5it3l@4ax.com>
On Tue, 9 Mar 2010 02:09:09 -0800 (PST), Javas <deepan.17@gmail.com>
wrote, quoted or indirectly quoted someone who said :

import java.util.*;
public class Qn353
{
       private String name;
       public Qn353(String name)
       {
               this.name = name;
       }

       public boolean equals(Object o)
       {
               if ( ! (o instanceof Qn353) ) return false;
               Qn353 p = (Qn353) o;
               return p.name.equals(this.name);
       }
       public static void main(String [] args)
       {
               HashSet<Object> hs = new HashSet<Object>();
               hs.add(p1);
               hs.add(p2);
               System.out.println(hs.size());
       }
       public int hashcode()
       {
               return 1;
       }


This would not compile. You never define p1 and p2.
--
Roedy Green Canadian Mind Products
http://mindprod.com

The first 90% of the code accounts for the first 90% of the development time. The remaining 10% of the code accounts for the other 90% of the development time.
~ Tom Cargill

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