Re: Question about eliminating conditional logic

From:
Lew <noone@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Tue, 05 May 2009 00:35:29 -0400
Message-ID:
<gtofmi$6eu$1@news.albasani.net>
Adam Sandler wrote:

I'm having a hard time with implementing the notion of getting rid of
some "if then else" hell.

Given the following code sample:

if (i = 1)
{
  method1(i);
}
else if (i = 2)
{
  method2(i);
}
else if (i = 3)
{
  method3(i);
}
else (i = 4)
{
  method4(i);
}

I looked in Fowler's "Refactoring"... but replace conditional with
polymorphism doesn't seem to apply -- these aren't classes, they're


You could use polymorphism if you refactor the methods to be in different
implementations of a common type. More on that in a moment.

method calls. I looked at http://polygoncell.blogspot.com/2008/07/as-many-people-already-met-there-are.html
and all they did was replace the if block with switch. That doesn't


Nothing wrong with a switch, other than that it almost always masks a use case
for polymorphism.

really eliminate the conditional now does it? I also read somewhere


Nothing really eliminates the conditional, now does it?

else that I could use a map. The dilemma is my conditional calls
methods, not make assignments... so something like this really doesn't
work:

HashMap commandMap = new HashMap();
commandMap.put(1, method(1));
commandMap.put(2, method(2));
commandMap.put(3, method(3));
commandMap.put(4, method(4));


You need a functor, that is, a type that wraps a function. (All those guys
who favor closures are going nuts right now.)

So while I'm NOT asking the forum to do my work for me, I am an
applied learner... and given a couple of the sources I've cited in my
post, I don't quite get getting rid of this conditional logic yet.
What is the best way to get rid of this smell?


In the first place, stop calling it a "smell". You cannot get rid of the
conditional, because it's inherent to the logic. Your prejudice will undo you.

That said, I'd do it something like this, using polymorphism (each type to its
own source file, which I have not tried or compiled myself yet), without a lot
of error checking, ignoring exceptions, etc.:

public interface Command
{
   public void command( int arg );
}

public class CommandA implements Command
{
   @Override // use if at least Java 6
   public void command( int arg )
   {
     System.out.println( "A arg = "+ arg ); // example only
   }
}

public class CommandB implements Command
{
   @Override
   public void command( int arg )
   {
     System.out.println( "B arg = "+ arg );
   }
}

public class CommandC implements Command
{
   @Override
   public void command( int arg )
   {
     System.out.println( "C arg = "+ arg );
   }
}

public class CommandD implements Command
{
   @Override
   public void command( int arg )
   {
     System.out.println( "D arg = "+ arg );
   }
}

public class RefactoredExample
{
   private final Map <Integer, Command> commands;

   /** Constructor. */
   public RefactoredExample()
   {
     Map <Integer, Command> cmds = new HashMap <Integer, Command> ();
     cmds.put( 1, new CommandA() );
     cmds.put( 2, new CommandB() );
     cmds.put( 3, new CommandC() );
     cmds.put( 4, new CommandD() );
     commands = Collections.unmodifiableMap( cmds );
   }

   public void doCommand( int chooser, int arg )
   {
     Command cmd = commands.get( chooser );
     if ( cmd != null )
     {
       cmd.command( arg );
     }
   }
}

public class Client
{
   public static void main( String args [] )
   {
     RefactoredExample eg = new RefactoredExample();
     int chx = Integer.parseInt( args [0] );
     int arg = Integer.parseInt( args [1] );
     eg.doCommand( chx, arg );
   }
}

A clever variation on this puts Class <? extends Command> objects as the
values in the map and instantiates the target object upon retrieval. There
are use cases for that.

--
Lew

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