Re: type combinations

From:
Thomas Hawtin <usenet@tackline.plus.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sat, 29 Apr 2006 22:00:55 +0100
Message-ID:
<4453e072$0$9233$ed2619ec@ptn-nntp-reader01.plus.net>
Stefan Ram wrote:

  I have a class whose instances are both an A and a B:

interface A {}
interface B {}
class C implements A, B {}

  The method ?m? needs to declare that it returns somthing that
  is also both an A and a B (but not necessarily a C).
  I try to express this via the type paramter ?T?:

<T extends A & B> T m(){ return new C(); }


It's the caller that determines exactly what T is. T need not be a
subtype of C. What you appear to be trying to do is:

     A&B m() { return new C(); } // Illegal.

or

     ? extends A&B m() { return new C(); } // Still illegal.

  I was hoping that the compiler (JDK 1.6 beta) would sse that
  ?new C()? satisfies this requirement. But the compiler
  reports:


C does not always satisfy the requirements. Consider:

class D extends C {}
....
     D d = YourClass.<D>m();

  How could the code be modified to express that:

    - m returns an object that implements (or ?extends?) both A and B, and
    - ?return new C()? is accepted within m's declaration for this purpose?


You cannot use intersection types other than for generic parameters (and
implicitly as the result of the ?: operator).

Tom Hawtin
--
Unemployed English Java programmer
http://jroller.com/page/tackline/

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