Re: Still no typedef

From:
Lew <lew@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 05 Dec 2007 21:23:23 -0500
Message-ID:
<naSdnW-XQbGBwMranZ2dnUVZ_rmjnZ2d@comcast.com>
Steve Wampler wrote:

John W. Kennedy wrote:

Patricia Shanahan wrote:

Steve Wampler wrote:

This isn't my area so feel free to tell me what I'm doing wrong, but
how would this be different than:

   class FooInt extends Foo<Comparator<Integer>> {}

Wouldn't this be legal already?

Similarly for:

   interface BazDouble extends Baz<Comparator<Double>> {}


FooInt would only have a default constructor, regardless of the
Foo<Comparator<Integer>> constructors.


Nonsense. You just define the constructors in the inherited class.

And Foo might be final in the first place.


Might be. Usually isn't.

Given that Java does not, at this time, sport a "typedef" keyword, the
class-derivation technique will work in quite many cases. In fact, it's a
very common idiom. There are an awful lot of heritable classes to which this
would apply.

class Dao<T extends Entity> {...}
class User extends Entity {...}
class UserDao extends Dao<User> { ... stuff specific to User manipulation }

Of course, here we're doing much more than a typedef, we're actually defining
overrides and other specific behaviors for a User-level Dao class. We get the
compactness for free, this time.

--
Lew

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