Re: Comparable interface

From:
Daniel Pitts <googlegroupie@coloraura.com>
Newsgroups:
comp.lang.java.programmer
Date:
23 Apr 2007 08:28:22 -0700
Message-ID:
<1177342102.006143.269380@y80g2000hsf.googlegroups.com>
On Apr 23, 8:24 am, Daniel Pitts <googlegrou...@coloraura.com> wrote:

On Apr 23, 5:48 am, Hendrik Maryns <hendrik_mar...@despammed.com>
wrote:

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Andrew Thompson schreef:

Chanchal wrote:
..

this is the code i have written


Please read my original message again, carefully.
If there is anything that I did not make clear about
helping the reader, feel free to ask.
..

in this case if i do not return some thing even in the case of
throwing the exception, i have to retrn some value. otherwise the
class wont compile.


    public int compareTo(Object obj){
        ReportObject rObj;
        if(obj instanceof ReportObject ){
            rObj = (ReportObject)obj;

            if(this.positionNumber < rObj.getPositionNumber()){
                return -1;
            }else if(this.positionNumber == rObj.getPositionNumber()){
                return 0;
            }else if(this.positionNumber > rObj.getPositionNumber()){
                return 1;
            }

        }else{
            throw new ClassCastException(this +
                   " is not comparable to " + obj );
        }
        return -2;
    }


Funny, I would have expected a compiler error here about unreachable
code. The last line is unreachable, right?

Ah, no, it isn't. At least, the compiler cannot know: obj can be an
instance of ReportObject, and the getPositionNumber() method can vary
such that none of the inner conditions fits.

Anyway, why not simply

public int compareTo(Object obj){
    ReportObject rObj = (ReportObject)obj;
    if(this.positionNumber < rObj.getPositionNumber()){
        return -1;
    }else if(this.positionNumber == rObj.getPositionNumber()){
        return 0;
    }else if(this.positionNumber > rObj.getPositionNumber()){
        return 1;
    }

}

The JVM will throw the ClassCastException, no need to do that yourself.

And oh yes, you might try to venture into generics, in which case the
problem will go away all by itself:

class ReportObject implements Comparable<? super ReportObject> {

...

public int compareTo(ReportObject obj){
    if(this.positionNumber < obj.getPositionNumber()){
        return -1;
    }else if(this.positionNumber == obj.getPositionNumber()){
        return 0;
    }else if(this.positionNumber > obj.getPositionNumber()){
        return 1;
    }

}

...

}


You might ALSO venture into using some basic logic.

if (a < b) {
   return -1;} else if (a > b) {
   return 1;
}

return 0;

it is highly (100%) likely that if (!(a < b) && !(a > b)), then a ==
b. At least with primitive data types in Java.


Actually, I think I'm wrong.
NaN isn't == NaN, is it?
In any case, comparable should throw an exception in that case too, as
you can't order NaN.
Actually, if you are using floating point values, you can use
Double.compareTo or Float.compareTo.

Indeed, I would probably do this:

public int compareTo(ReportObject obj) {
   return Integer.compareTo(this.positionNumber,
obj.getPositionNumber());
}

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