Re: Java puzzler

From:
Joshua Cranmer <Pidgeot18@verizon.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Thu, 12 May 2011 10:33:34 -0400
Message-ID:
<iqgr40$p2d$1@dont-email.me>
On 05/11/2011 04:57 PM, Tom Anderson wrote:

If we're talking about things like:

byte b = 0;
b += 2;

The i agree that that should compile - it would be agonizing if it
didn't. But i see no earthly reason why this:

byte b = 0;
int i = 1000000;
b += i;

Should compile. Where you're using a literal, you have no way to make
the literal one size of integer or another, but when you're using a
variable, you do; an offset for a byte can be a byte itself.


Well, if you step back and look at it from the semantic point of view,
what the compiler sees at both instances the following pattern:
<variable of type byte> += <expression of type int>. You could redefine
literals of smaller numeric type, which makes the expression computation
rules confusing (is (1001 - 1000) a byte, short, or int?). However, as
long as byte, short, and char promote to int for integer computation, it
still doesn't solve the += problem. You could change them to not promote
to int, but that starts to cause interesting tangles in Java (the VM
would either need to have instructions for all arithmetic instructions
in byte, short, and char counterparts, in addition to the int, float,
long, and double counterparts, or it would have to emit narrowing
conversions after every subcomputation in an expression).

But I can see reasons to allow your `b += i' expressions. Consider that
use of the byte and short types are relatively rare, as they are only
effective in memory reduction when used in arrays [1]. It is not
unimaginable that many constants have type int but are naturally
applicable to byte or short values. In such a case, b += i would make sense.

So, would it have been possible to write the language rules such that
integer literals have either some sort of indeterminate-length
pseudo-type that can be used submissively in all sorts of expressions,
or to have small integer literals have type byte, bigger ones type
short, and so on?


Yes, it would have been possible, but if you throw in the results of
compile-time constant expressions, things might get ugly. It also makes
computing the type of a literal somewhat uglier for rather little benefit.

[1] Well, the JVM could theoretically pack bytes, shorts, and chars
inside classes, but I'm not sure if this is done in practice.

--
Beware of bugs in the above code; I have only proved it correct, not
tried it. -- Donald E. Knuth

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