Re: Server and multiple sockets

From:
Knute Johnson <nospam@rabbitbrush.frazmtn.com>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 22 Apr 2007 22:22:22 -0700
Message-ID:
<joXWh.8566$2Q1.5930@newsfe16.lga>
Chris wrote:

On Apr 22, 9:33 pm, Esmond Pitt <esmond.p...@nospam.bigpond.com>
wrote:

SadRed wrote:

On Apr 23, 7:59 am, Chris <cc_brews...@yahoo.com> wrote:

   public void run() {
       System.out.println("Server ready.");
           int i = 1;
           System.out.println("Start of ");
           try {
           System.out.println("Start of connecting section. i = " +
i);
// *** EXECUTES CORRECTLY TO HERE
               ServerSocket ss = new ServerSocket(port);

You are re-creating the same server socket each time
new client is created.

Absolute rubbish. He isn't.

Chris, your code is mostly fine except that you should always close
output streams of a socket before the input, and in fact once you've
done that closing the input stream or the socket is redundant. I also
don't know why you're starting the client thread and then immediately
interrupting it - don't do that.

Your problem is coming when restarting the server. Use new
ServerSocket(), then call serverSocket.setReuseAddress(), then
serverSocket.bind() to get around this.


Does this apply even when I've just started the program? Because I get
an error on the first time. Also, since my "new ServerSocket"
statement is what causes the error, your other calls wouldn't affect
it if they came after it. One more question: I don't understand the
argument type for bind() -- it won't take the port number I'm using.
Thanks for your help.


What port are you using? Does some other program have that port
listening? Try netstat -a before your run your program to see what's
going on.

--

Knute Johnson
email s/nospam/knute/

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