Re: ordering of items in a treemap

From:
Lew <lew@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 07 Apr 2008 08:47:13 -0400
Message-ID:
<fISdnU6TGJpMimfanZ2dnUVZ_gSdnZ2d@comcast.com>
Andrea Francia wrote:

angelochen960@gmail.com wrote:

Hi,

I have code:

TreeMap<String, String> shoeSize = new TreeMap<String, String>();

shoeSize.put("8", "8");
shoeSize.put("8.5", "8.5");
shoeSize.put("10", "10");
System.out.println(shoeSize.toString());

I got:

{10=10, 8=8, 8.5=8.5}

I'd like to get the order same inserted:

{8=8, 8.5=8.5, 10=10}

any idea? thanks


 From TreeMap docs:
 > The map is sorted according to the natural ordering of its keys, or
by a Comparator provided at map creation time, depending on which
constructor is used.

Create a subclass that log the order of the inserted keys and create a
Comparator that uses these information.


That'd be an implementing class of java.util.Comparator. It's a subtype, but
not a subclass. What class were you suggesting to extend?

There's no need for the additional complexity and overhead of logging
anything. Just write a Comparator and pass it to the TreeMap constructor.

You can't use a List instead?


Good suggestion - note that the Map as shown does not associate keys to
values, but values to themselves. OTOH, the List won't sort it for you, so
you still need to write a Comparator.

--
Lew

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