Re: array operation

From:
Lew <noone@lewscanon.com>
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 18 Dec 2009 23:40:17 -0500
Message-ID:
<hghlfi$7cj$1@news.albasani.net>
NickPick wrote:

How can i [sic] delete an element from an array and have the size of the
array adjusted accordingly? If I have an array of 10 elements and
delete [5] I want all elements above [5] to move down by one. Is this
possible?


markspace wrote:

Yes, but it's expensive. That is, it takes a lot of computer processing
time to move those elements down by one, comparatively speak.

Consider using a List<> instead, like ArrayList or LinkedList. Both of
these provide the behavior you want, and they can be swapped out for
each other depending on the exact operations you want to be fast.


Since ArrayList is backed by an array, all it's doing is hiding the exact same
operations as doing it by hand, isn't it?

Also, look at HashSet and HashMap, both of which offer faster removal
and faster access, on average, then List or arrays.

<http://java.sun.com/docs/books/tutorial/collections/implementations/index.html>


HashSet and HashMap, or more generally, Set and Map have very different
behaviors from arrays or Lists. A Set cannot contain more than one element
that compare equal but a List can. A List element can be accessed by its
integer index, but a Set element cannot be. A Map contains entries in pairs,
a key and value for each entry, but other types of collections just contain
single-valued elements. There are so many more delightful collection classes
to choose from, too.

In any event, the referenced link and the Javadocs for the different
Collections classes contain information about their characteristics and their
expected or average performance, e.g., HashSet has approximately constant-time
access for insertion and retrieval.

--
Lew

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