Re: inheriting a main method

From:
Leif Roar Moldskred <leifm@huldreheim.homelinux.org>
Newsgroups:
comp.lang.java.programmer
Date:
Mon, 14 Sep 2009 09:48:09 -0500
Message-ID:
<7cidnXN0__M0yjPX4p2dnAA@telenor.com>
Ross <rossclement@gmail.com> wrote:

Thanks, but that doesn't quite work as intended. I have written two
classes:

public class Test
{
 public static void main( String args[] )
 {
   Thread mainThread = Thread.currentThread();
   StackTraceElement[] currentStack = mainThread.getStackTrace();
   StackTraceElement mainStackElement = currentStack
[ currentStack.length - 1 ];

   System.out.println( "My main class is " +
mainStackElement.getClassName() );
 }
}

That works fine if I run it, and reports the class as "Test". But I
then create a child class.

public class Test2 extends Test
{
}

If I then run:

$ java Test2

I get the output:

My main class is Test

When what I want is:

My main class is Test2

Any ideas on how to find out the name of the executed class rather
than the ancestor class which has the main method?


Ow. Don't do that. For one thing, I don't think there _is_ any way
to retrieve the name of the class mentioned on the command line
in this case. More importantly, it's bad design.

I'd recommend you make an inherited business method, then write
explicit main methods for all the classes that will use it (There
can't be _that_ many of them, and it make it a lot easier to
understand what's happening.)

Something like this:

public abstract class BaseClass {
  protected void doStuff( String[] args ) {
    // Do whatever you're supposed to do
  }
}

public class SubClass extends BaseClass {
  public static void main( String[] args ) {
     BaseClass myFoo = new SubClass( );
     myFoo.doStuff( args );
  }
}

If you have common initialization that needs to be done, use an
inherited initialization method as well:

  public static void main( String[] args ) {
    BaseClass myFoo = new SubClass( );
    myFoo.initialize( args );
    myFoo.doStuff( );
  }

--
Leif Roar Moldskred

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