Re: can't throw

From:
bob smith <bob@coolfone.comze.com>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 12 Sep 2012 11:40:58 -0700 (PDT)
Message-ID:
<e726309e-8aa2-45e7-8452-80f1c2ef1b3f@googlegroups.com>
On Wednesday, September 12, 2012 1:32:01 AM UTC-5, Robert Klemme wrote:

On 11.09.2012 22:16, bob smith wrote:
 

Am I the only one who wanted to throw an Exception but couldn't

 

because I was overriding a method that threw nothing?

 

 

In particular, I'm subclassing Thread and can't throw an Exception in

 

the run method. I suspect this is a more general issue though.

 
 
 
Why are you subclassing Thread in the first place?
 
 
 
Kind regards
 
 
 
    robert
 
 
 
--
 
remember.guy do |as, often| as.you_can - without end
 
http://blog.rubybestpractices.com/


There are two ways to create a new thread of execution. One is to declare a=
 class to be a subclass of Thread. This subclass should override the run me=
thod of class Thread. An instance of the subclass can then be allocated and=
 started. For example, a thread that computes primes larger than a stated v=
alue could be written as follows:

     class PrimeThread extends Thread {
         long minPrime;
         PrimeThread(long minPrime) {
             this.minPrime = minPrime;
         }
 
         public void run() {
             // compute primes larger than minPrime
              . . .
         }
     }
 
The following code would then create a thread and start it running:

     PrimeThread p = new PrimeThread(143);
     p.start();

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