Re: Multi threading - how small is the smallest 'unit' of code

From:
Eric Sosman <esosman@ieee-dot-org.invalid>
Newsgroups:
comp.lang.java.help
Date:
Sat, 01 Jan 2011 09:41:33 -0500
Message-ID:
<ifneg6$oq6$1@news.eternal-september.org>
On 1/1/2011 8:13 AM, azserrata wrote:

Say:

//CODE1
(...)
sharedVariable ++;
int i = sharedVariabel;


     ITYM `sharedVariable', here and in various other spots.

boolean test=(i==sharedVariable);
(...)

If the code is executed in multiple threads, in a non-synchronized
piece of code, it is possible that 'test' might be FALSE.


     Yes. Even worse, `sharedVariable' might have some completely
bizarre value, because each thread does an unsynchronized read-
modify-write on it.

What about these, all non-synchronized.

//CODE2
(...)
int i = (++sharedVariabel);
boolean test=(i==sharedVariable);


     Same problem.

Or even:

//CODE3
(...)
int i;
boolean test=((i=(++sharedVariabel))==sharedVariable);


     Same problem.

Or the "extreme":

//CODE4
(...)
sharedVariable++;
boolean test=(sharedVariabel==sharedVariable);


     Same problem.

Is it possible to guarantee that == is implemented (internally) as a
unique, indivisible, instruction?


     The Java language has no such guarantee, since "instruction" is not
part of the definition of Java. The `volatile' qualifier may help with
what you need, but not with what you actually asked.

Or is it possible that other thread might do its increment
(sharedVariable++) somewhere in-between and this thread's 'test' ==
FALSE?


     Yes. And without synchronization (or `volatile'), there's no
telling when the other thread's modification might become visible
to this thread.

Thank you for your comments and have a great 2011.


     What problem are you trying to solve? There's probably a way
to solve it without taking so many risks.

--
Eric Sosman
esosman@ieee-dot-org.invalid

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