Re: reading the JLS (17.4.5)

From:
Patricia Shanahan <pats@acm.org>
Newsgroups:
comp.lang.java.programmer
Date:
Wed, 21 Dec 2011 10:46:07 -0800
Message-ID:
<ZM-dnX6Q9_DotG_TnZ2dnUVZ_vOdnZ2d@earthlink.com>
On 12/21/2011 12:37 AM, Andreas Leitgeb wrote:

Lew<lewbloch@gmail.com> wrote:

Andreas Leitgeb wrote:

Given some (simplified) sample code:
   class Test {
      /*non-vol*/ int n1;
      volatile int v1;

      void t1() {
        n1 = 1;
        v1 = n1; // v1 uses n1
      }

      void t2() {
        int r1=v1, r2=r1*n1; // r2 uses r1
        assert ! (r1 == 1&& r2 != 1) : "huh?";
      }
   }
Two threads T1 and T2 may at some point run t1() and t2()
respectively, then I should expect, per transitivity of

You have to establish a /happens-before/ between the invocations
of t1() an t2().
If two threads begin to execute the methods, you cannot guarantee
that t1() will /happen-before/ t2(), so the read of 'v1' in the
latter could result in the default value.


Perhaps you found the/a sore spot of my (mis?)understanding.

*iff* a *volatile* read gets to see the result of a *volatile*
write, then doesn't that say anything about that the write must
have "happened-before" the read?

In my example, I didn't mean to imply, that r1 would always
turn out to be 1. But *if* it does, then could anything be
assumed about r2 ?

If the write to v1 (but not to n1) in t1() were in a
synchronized(this)-block, and so were the read of v1
(but not n1) in t2(), then would anything be implied
about r2 *if* observing r1 == 1 in T2?

In practice, I think that establishing a happens-before
based on observation of a read's value is quite essential,
but I may of course be wrong here. I don't even see how one
could determine the order in which synchronized blocks for
a common monitor are actually passed through by different
threads, other than by observing reads.


I think we need to distinguish between two things. I'm going to copy
some notation from Lew. /happens-before/, printed in italics in the JLS,
is not an observation about what really happened, but a requirement of
the form "X must appear to happen before Y", with a definition of what
that means in terms e.g. of the results of read operations.

That is entirely distinct from the actual order of operations. If a read
sees the result of a write, that write must have really happened before
(no slashes, no italics) the read, but that does not prove the existence
of a /happens-before/ relationship between them.

However, the volatile reads and writes are synchronization actions, so
they are ordered by the synchronization order, and whichever comes first
in the synchronization order /happens-before/ the other. I agree with
your assertion.

Patricia

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