Re: ClassLoaders and finding fully-qualified names

From:
=?ISO-8859-1?Q?Arne_Vajh=F8j?= <arne@vajhoej.dk>
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 29 Dec 2006 16:04:11 -0500
Message-ID:
<459582bf$0$49202$14726298@news.sunsite.dk>
ballpointpenthief wrote:

A user selects the Hello.class file from a JFileChooser.
The Hello.class file is sent to subclass of SecureClassLoader.
The ClassLoader needs the fully-qualified classname (mypackage.Hello)
to define the class (along with the bytecode, and the CodeSource),
so....

how can I find out that Hello is in 'mypackage' if all I have is the
File?


You can specify null to defineClass.

Here are a standalone example:

package december;

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;

public class ClassnameFinder {
     private static byte[] load(String fnm) throws IOException {
         File f = new File(fnm);
         byte[] b = new byte[(int)f.length()];
         InputStream is = new FileInputStream(f);
         is.read(b);
         is.close();
         return b;
     }
     public static String getClassname(String fnm) throws IOException,
ClassNotFoundException {
         ClassnameFinderHelper help = new ClassnameFinderHelper();
         return help.getClassname(load(fnm));
     }
     public static void main(String[] args) throws Exception {
         System.out.println(getClassname("C:\\X.class"));
     }
}

class ClassnameFinderHelper extends ClassLoader {
     public String getClassname(byte[] bc) {
         return defineClass(null, bc, 0, bc.length).getName();
     }
}

Arne

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