Re: changing array dimension in a method

"Daniel Malek" <daniel_malek001@hotmail.com> writes:


  You can not change the dimension of an array in the same
  sense that suggest that you can not change the value of
  the number 3.

  You can, however, create a new array with another dimension
  at run-time.

  The following example code shows how to create and populate an
  array, when the dimension becomes only known at run-time.

  In this example, an array with 3 dimensions of sizes 4, 5, and
  6, respectively, is created, filled, and printed.

public class Main
{
  public static int[] cdr( final int[] list )
  { return java.util.Arrays.copyOfRange( list, 1, list.length ); }

  public static java.lang.Object build( final int ... extensions )
  { final java.lang.Object array = java.lang.reflect.Array.newInstance
    ( java.lang.Integer.TYPE, extensions );
    for( int i = 0; i < extensions[ 0 ]; ++i )if( extensions.length > 1 )
    java.lang.reflect.Array.set( array, i, build( cdr( extensions )));
    else java.lang.reflect.Array.setInt(( int[] )array, i, i );
    return array; }

  public static void print( final java.lang.Object array )
  { for( int i = 0; i < java.lang.reflect.Array.getLength( array ); ++i )
    if( array.getClass().getName().startsWith( "[[" ))
    print( java.lang.reflect.Array.get( array, i )); else
    java.lang.System.out.print( java.lang.reflect.Array.getInt( array, i )); }

  public static void main( final java.lang.String[] args )
  { print( build( 4, 5, 6 )); }}