Re: Immutable object graph
On May 24, 10:51 am, "visionset" <s...@ntlworld.com> wrote:
"Mike Schilling" <mscottschill...@hotmail.com> wrote in message
news:d7k5i.29992$Um6.19483@newssvr12.news.prodigy.net...
"visionset" <s...@ntlworld.com> wrote in message
news:SNf5i.3025$I55.1261@newsfe2-gui.ntli.net...
I have a graph of Leafs and Nodes.
A Node has 0...n Leafs
A Leaf has 1...2 Nodes.
The referencing is circular.
During execution I wish to modify both Nodes (eg add/remove Leafs) and
Leafs (eg add a Node to a single Noded Leaf).
The Leaf is easy to make Immutable, but does it make sense to make the
Node immutable?
It seems to me that
I wish to modify both Nodes and Leafs
and
The Leaf is easy to make Immutable
contradict each other.
When I wrote that I thought, 'shall I be totally precise or will it get the
point accross?' ...Alas.
So by modify an immutable I mean obtain an instance that reflects the new
state I require.
I mean it really goes without saying, you can't Modify an Immutable, doesn't
it?
Leaf newLeaf = oldLeaf.withNewFoo(myFoo);
--
Mike W
So, your object graph itself is not immutable, but the nodes within it
may be? That doesn't quite make sense either.
In any case, isn't a Leaf just a type of Node? Often they are
implemented using the same class, as their behavior is the same.
Another common approach is a Node class and an Edge class.
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