Re: help with extends
John Smith wrote:
class above {
Class names should start with an upper-case letter, by ironclad convention.
void display() {
class family {
-- some functions --
}
class creature extends family {
public void creature() {
} // default constructor
This is not a constructor. Constructors do not have return types ('void'). A
constructor would have the form:
public Creature()
Side note: the term "default" constructor refers to the no-arg, no-exception
constructor when it's generated by the compiler. We do tend to call it the
"default" when we code it explicitly, but that's not strictly correct.
Pull back on those excessive indentations for Usenet - 2 spaces is enough,
four about the maximum per indent level.
public void creatureObj(obj y) {
Get rid of the return type. To invoke a different superclass constructor from
'super()', call it explicitly:
super( y );
-- some functions --
Should not have overridable functions in a constructor.
} // creatureObj's constructor
Not a constructor if it's a method, i.e., has a return type. Methods should
not have the same name as the class in which they're declared.
I know I'm actually calling the default constructor which returns
everything as null in the output such as for inputCreature.getName(). So
the code above is wrong.
You have defined no constructors in the code you posted.
How should I code it such that it calls the corresponding value for
inputCreature.getName() ?
I don't know if I understand the question, but if 'getName()' is not a final
method, you should not call it from a constructor.
class Creature extends Family
{
public Creature( Foo f )
{
super( f );
// more logic - but NO overridable methods
}
}
Read the tutorial:
<http://java.sun.com/docs/books/tutorial/index.html>
--
Lew