Re: what is the bettter/performant way to compare org.w3c.dom.DocumentFragment

=?ISO-8859-1?Q?Arne_Vajh=F8j?= <>
Tue, 17 Jan 2012 21:56:42 -0500
On 1/17/2012 9:33 PM, Jeff Higgins wrote:

On 01/17/2012 08:56 PM, Mausam wrote:

On Tuesday, 17 January 2012 23:02:29 UTC+5:30, Jeff Higgins wrote:

On 01/17/2012 10:03 AM, Mausam wrote:

I have a java class, whose contains a DocumentFragment.

In the equals method of my class, I am converting the
DocumentFragment to a String and comparing an equals on the String.

I know this is not the best way, because "attributes" e.g can change
order in Element of DocumentFragment, or e.g documents differ only
in the sequence of unordered elements.

So in such cases this equality will fail.

Please suggest a better approach.

A my class is equal to another my class if and only if ...

Thanks Jeff, I understand what you mean.

BTW, I was checking the API

The attributes NamedNodeMaps are equal. This is: they are both null,
or they have the same length and for each node that exists in one map
there is a node that exists in the other map and is equal, although
not necessarily at the same index.

The childNodes NodeLists are equal. This is: they are both null, or
they have the same length and contain equal nodes at the same index.
Note that normalization can affect equality; to avoid this, nodes
should be normalized before being compared.

Here for attributes, they take care of "NOT necessarily at the same
index" but in case of childNodes its not being taken care of. So if
there is a sequence of unordered elements (<emp/><dept/>
and<dept/><emp/> ) they will be treated as NOT equal.

So either I iterate through each node and attribute and do a
comparison. That's the fall back. But before that, I wanted to check
the experts if there are better options.

Yep. I based my hair trigger response upon the .equals(Object) of the
"known implementing classes" of Node. Sorry. I'll be interested in
finding out the "cost" associated with Arne Vajh?j's response.

The cost is CPU time. It cost a bit of CPU time to parse and
reorganize and serialize again.


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