Re: can this code be improved

From: (Stefan Ram)
17 Aug 2006 01:10:02 GMT
<> (Stefan Ram) writes:

sort.put( -map.get( i ), i );

  This attempt to "invert" a map still has a bug: If two keys of
  the original map have the same value, one of them will be
  lost. The following solution uses a small "bias" added to
  each value, to make it different from every other value.
  (It might fail under some conditions.)

class NumericMapUtils
{ public static <D> void addTo
  ( final java.util.Map<D,java.lang.Integer> map, final D d, final int i )
  { map.put( d, i +( map.containsKey( d )? map.get( d ): 0 )); }}

public class Main
{ static final java.util.Random rand = new java.util.Random();
  public static void main( java.lang.String[] args )
  { final java.util.Map<java.lang.Integer,java.lang.Integer> map
    = new java.util.HashMap<java.lang.Integer,java.lang.Integer>( 50 );
    final int k = 1000; for( int i = 0; i < k; ++i )
    NumericMapUtils.<java.lang.Integer>addTo( map, rand.nextInt( 49 ), 1 );
    final java.util.SortedMap<java.lang.Double,java.lang.Integer> sort
    = new java.util.TreeMap<java.lang.Double,java.lang.Integer>();
    int j = 0; for( final java.lang.Integer i : map.keySet() )
    sort.put( -map.get( i )+ j++ * .8 / k, i );
    int c = 0; for( final java.lang.Double d : sort.keySet() )
    { java.lang.System.out.println
      ( "Rank " +( c + 1 )+ " number is " + sort.get( d ));
      if( ++c >= 6 )break; }}}

  A more clean solution might replace each key of the map
  "sort" by a ComparablePair of both the key and its value.

  I even have implemented such a beast

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