Re: Hash Code Compression

From:
Daniel Pitts <googlegroupie@coloraura.com>
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 11 Jan 2008 15:28:59 -0800 (PST)
Message-ID:
<9b5f331b-bb62-435d-a636-a547536a5e95@v29g2000hsf.googlegroups.com>
On Jan 11, 3:20 pm, j1mb0jay <n...@none.com> wrote:

Daniel Pitts wrote:

On Jan 11, 3:05 pm, j1mb0jay <n...@none.com> wrote:

Eric Sosman wrote:

j1mb0jay wrote:

I am currently working on a dictionary populating program. I currently
have a socket connection my local news server and am trawling through
all of the articles looking for new words. Java's String class has a
method that hashes strings. I was wondering if i should still be using
these even though I have over two million words in the hash table.
Although the hash table is currently Big 0(4).

    This makes no sense. O(4) = O(1) = O(0.01) = O(1000000),
by definition. What do you really mean?

I am using the Multiply Add and Divide (MAD) method for the
compression of the hash code, does Java have any built in
functions(methods) that will do this for me, or does anyone know of a
more efficient way?

    The value delivered by hashCode -- for any class, not
just for String -- is a Java int, 32 bits wide. How (and why)
are you "compressing" this value?

My hash table is made up of an array of n LinkedLists (where n is a
prime number that is roughly double the number of words in the dictionary).

I firstly use the String.hashCode() method on a given word. I then
compress this number so that i can use it as a index into the array of
LinkedList; as this 32bit number is often far to large. I then insert
the word into the LinkedList array at the compressed value index(The
fact the hashTable is an array of LinkedLists is so that it handles
collisions)

After inserting all of the words into the dictionary the largest
LinkedList in the array has only four elements. I thought Big O(4) was
the correct way of describing this.

Would it help if i posted my classes on here, or offer you a place to
download the program.

j1mb0jay


Why aren't you using the existing HashMap class?

If you want a compact representation of the words you come across,
consider a prefix tree data structure instead.

Just so you know, Big O measures the dominant term without
multipliers, For instance, if your algorithm takes N *n + N + 4
steps, then it is O(N*N). If it takes 4*n*n steps, it is still O(N*N)


I have been asked to create my own data structures to help aid
understanding for the course material for my degree module.(Check
article header)

Because i am currently building the dictionary file by trawling news
articles each word I pull from an article needs to be checked in the
dictionary to see if we already have it(I don't want to store each word
more than once). My current methodology means I only have to look at a
maximum of 4 words(out of 2.5 million) to see if I already have this
word stored in memory. Does this still mean my retrieval method is Big(N
Squared)

j1mb0jay


Actually, it means it has Big O(1) (As hash tables tend to)

Don't use the hash for the index in the linked list. Don't even
BOTHER with indexes in the linked list. The hash should be an index
into an array of lists (of whatever sort, linked or otherwise).

Then each list should be relatively small, so trivial to search/
insert.

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