Re: I have doubt

From:

Patricia Shanahan <pats@acm.org>

Newsgroups:

comp.lang.java.programmer

Date:

Tue, 14 Aug 2007 05:52:42 -0700

Message-ID:

<13c39d2qo9nbrd0@corp.supernews.com>

Like many expressions, evaluation of x++*++x requires the use of a
couple of temporary storage locations. In the bytecode model, they will
be locations on the virtual machine's stack, but most real machines use
registers instead.

Either way, I would not expect any memory to be allocated during
evaluation of the expression.

Patricia

Manju wrote:

hii

thanks for reply. I perfectly agree with u but when I think about
memory allocation of this expression I am not able to analyze it.
Could u explain that??

Best Regards

Manjiri (Manju)

On Aug 14, 2:34 pm, "LewyG" <lewynewsgr...@gazeta.pl> wrote:

"Manju" <manjiri...@gmail.com> wrote in message

news:1187082187.867372.205060@z24g2000prh.googlegroups.com...

int x=2;
int y;
y=x++*++x;
For this output is 8
I would like to know how this internally works

y = 2 [3] * [4] 4;

y = 2*4 = 8;

in [] is value after incrementation to show how this goes.