Re: Distinct ID Number Per Object?

From:
"Daniel Dyer" <"You don't need it">
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 17 Jun 2007 00:47:14 +0100
Message-ID:
<op.tt1gc0gz8kxvgr@jack.local>
On Sun, 17 Jun 2007 00:25:59 +0100, Hal Vaughan <hal@thresholddigital.co=
m> =

wrote:

Twisted wrote:

...

public class Base {
    public final long id; // should stay unique even on 64-bit
architectures, or with long running systems
    private static long idGenerator;
    public Base () {
        synchronized (Base.class) {
            id = idGenerator;
            idGenerator++;
        }
    }
    ...
}


There may be nothing to this, but, as I've said in this thread before,=

  =

and
said on this group many times, being self taught, I know there are man=

y

things I've missed. Is there any particular reason for you using this=

:

      id = idGenerator;
      idGenerator++;

Instead of this:

      id = idGenerator++;


The first example is less confusing. The single-line variant is modifyi=
ng =

two variables. And if you don't think the second example has the =

potential for confusion, you may be surprised that is not semantically =

equivalent to the first (it does something different).

You might want to write a little program to demonstrate the difference =

between these two assignments.

    id = idGenerator++;

    id = ++idGenerator;

Anyway, for a simpler version of the same idea implemented in Twisted's =
 =

code, just use java.util.concurrent.atomic.AtomicLong. It deals with th=
e =

synchronisation and incrementing for you.

Dan.

-- =

Daniel Dyer
http//www.uncommons.org

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