Re: ArrayList - Reading and writing

From:
Daniele Futtorovic <da.futt.news@laposte.invalid>
Newsgroups:
comp.lang.java.programmer
Date:
Sun, 20 Jul 2008 00:58:05 +0200
Message-ID:
<g5trb8$v1e$1@registered.motzarella.org>
On 2008-07-20 00:48 +0100, Daniel Pitts allegedly wrote:

Daniele Futtorovic wrote:

On 2008-07-15 16:07 +0100, Jimmie Tyrrell allegedly wrote:

That was perfect. I had tried using synchronized before - wasn't
aware that _both_ operations needed to be synchronized. It seems
overtly logical now :)

Thanks for the help!


The problem with shakah's approach is that it monopolises the List
Object during the whole process of Iteration -- which may go down well,
but which may also pose some problems.

It would be better to iterate over a copy. You'd still synchronise the
process of copying, as well as the process of adding.

For instance (non-generic code for the sake of simplicity):

List myQueue = ...;

/* adding */
synchronized( someLock ){
  myQueue.add(newObject);
}
/* end adding */

/* iterating */
List copy;

synchronized( someLock ){
  copy = java.util.Collections.unmodifiableList(myQueue);
}

for(Iterator it = copy.iterator(); it.hasNext();){
  //do something involving it.next();
}
/* end iterating */

Note that copying the List doesn't involve copying its /content/.


And what you did doesn't copy the list either, it just wraps it. To copy
it you'd actually have to use new ArrayList(someQueue);


Yes, I'd corrected that in a sucessive post.

The thing is,
that this process ALSO iterates over the whole list (although only for a
fast reference copy).

I had just made a suggestion that is another way to solve the OPs
problem, using new Java 1.5 Concurrency API features.

The approach to take depends on the size of the list, and the required
performance characteristics of the UDP handler.


Now that you mention it -- yeah, his scenario really calls for a
blocking queue. Although I had even named a variable in the sample code
I posted thus, I had focussed my attention too strongly on the iteration
part.

Thanks for improving the answers.

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