Re: String.valueOf() Memory Leak inside of thread.

From:
Robert Klemme <shortcutter@googlemail.com>
Newsgroups:
comp.lang.java.programmer
Date:
Fri, 11 Aug 2006 13:52:11 +0200
Message-ID:
<4k39bbFadedcU1@individual.net>
On 10.08.2006 21:52, BLlewellyn@gmail.com wrote:

If anyone could shed some light, I'd appreciate it.

I have a simple class with a main method. Inside the main method is a
loop. Each iteration of that loop instantiates an anonymous thread
whose run method contains a single line:

String str = String.valueOf(1);

This is causing a memory leak. If I change the line to read "String
str = "String.valueOf("1"); there is no problem. Also, if I do
something like: String str = "Hello world!"; there is also no problem.

If I use String.valueOf(1); inside the loop but outside of the thread,
there is no problem. Can anyone see why garbage collection is not
occurring inside the thread?

Thanks.

--Bradley

public class Main {
     public static void main(String[] args) {
          Thread thread = null;
          for ( int intLoop = 0; intLoop < 10000; intLoop++ ) {
               String myString;
               myString = String.valueOf(1);
               thread = new Thread() {
                    public void run() {
                         String str = String.valueOf(1);
                    }
               };
               thread.start();
               thread=null;
               System.gc();
          }
     }
}


Some things to consider:

1. IIRC System.gc() is just a hint. There is no guarantee that GC will
actually start at that moment.

2. There is no timely correlation between thread termination and
System.gc(), i.e. the string might not yet have been created when gc()
is invoked.

3. Generally the JVM is very free to decide when GC occurs. I doubt it
will create GC overhead if there is just a single (or a few) new objects
on the heap.

4. Your other examples do not exhibit the behavior you seem to observe
because they don't create new instances.

Kind regards

    robert

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