Re: Calling inherited protected method fails to compile

From:
"Alf P. Steinbach" <alfps@start.no>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 13 May 2008 12:12:06 +0200
Message-ID:
<zPydnRlJ1uDl9LTVnZ2dnUVZ_hWdnZ2d@posted.comnet>
* nomad:

Anyone have any idea why the code below fails to compile? I get the following
message when I try:

     error C2660: 'B::F' : function does not take 2 arguments.'

Clearly, B should inherit int F(int, int) from A, the function declaration
is not ambiguous in any way, so it seems to me that I should be able to call
it, yet the compiler refuses to allow me to do it. If I explicitly reference
it (i.e., A::F(x, 3) instead of this->F(x, 3)), it works fine.


This is a FAQ (see below).

class A
{
    public:
        A(void) { };
        virtual int F(int x) = 0;

    protected:
        int F(int x, int y)
        {
            return x + y;
        }
};

class B : public A
{
    public:
        B(void) { };

        virtual int F(int x)
        {
            return this->F(x, 3);
        }
};

int main(void)


This 'void' is a C-ism. Not that it matters much, just a fine detail.

{
    B b;

    (void) b.F(3);

This cast is completely unnecessary.

}


For your question about why you get a compilation error, see the FAQ
item titled "What's the meaning of, Warning: Derived::f(char) hides
Base::f(double)?", currently item 23.9, available at e.g. <url:
http://www.parashift.com/c++-faq-lite/strange-inheritance.html#faq-23.9>,
or any mirror.

It's often a good idea to check the FAQ first.

Cheers, & hth.,

- Alf

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