Re: Double-Checked Locking pattern issue

From:
"Ben Voigt [C++ MVP]" <rbv@nospam.nospam>
Newsgroups:
microsoft.public.vc.language
Date:
Wed, 2 Jan 2008 11:22:06 -0600
Message-ID:
<#RtAFPWTIHA.3676@TK2MSFTNGP06.phx.gbl>
"George" <George@discussions.microsoft.com> wrote in message
news:D8AE73B1-06F4-4A4B-9986-11DF04C9165B@microsoft.com...

Thanks Ben,

I understand generally how pipeline works. :-)

But I am not sure how (if for the purpose of pipeline, compiler do the
re-ordering) the general rules applies to my specific case. Any ideas?


Out of order execution is reordering in the CPU, not the compiler, to make
more efficient use of the pipeline.

regards,
George

"Ben Voigt [C++ MVP]" wrote:

"George" <George@discussions.microsoft.com> wrote in message
news:AFF9AD5D-1564-4099-AA56-C36A23EA124B@microsoft.com...

Thanks Igor,

to memory is expensive, it is conceivable the CPU may reorder the
write
to the pointer as early as possible.


The only reason I could think of is writing earlier to memory could
save
the
register and we could save the register for later use.

What are your points about why writing early will improve performance?
Could
you show more description or some pseudo code please?


You aren't considering pipelining, cache effects, speculative branching,
or
any of the other things that new CPUs use to retire multiple instructions
per clock.

In short, while some CPU can retire four instructions per clock, there
aren't four copies of every unit, and certainly it can't transfer that
much
to/from memory at once. So the CPU reorders instructions to get
different
instructions that use different parts of the CPU executing together. In
essence, this is what hyperthreading also does, except it interleaves a
separate flow of execution instead of reordering a single flow.

All of this is part of the reason that function calls are so very
expensive.

regards,
George

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