Re: Why I can not use NetQueryDisplayInformation in a service?

From:
"zhang" <makefriend8@163.com>
Newsgroups:
microsoft.public.vc.language
Date:
Tue, 6 Feb 2007 10:53:44 +0800
Message-ID:
<uo5wKmZSHHA.5068@TK2MSFTNGP03.phx.gbl>
what should I do?
change this?
CreateService(
        schSCManager, // SCManager database
        lpszDisplayName, // name of service
        lpszDisplayName, // service name to display
        SERVICE_ALL_ACCESS, // desired access
        SERVICE_WIN32_OWN_PROCESS, // service type
        SERVICE_DEMAND_START, // start type
        SERVICE_ERROR_NORMAL, // error control type
        lpszBinaryPathName, // service's binary
        NULL, // no load ordering group
        NULL, // no tag identifier
        NULL, // no dependencies
        NULL, // LocalSystem account
        NULL);
or change
{
ServiceStatus.dwServiceType =
      SERVICE_WIN32;
   ServiceStatus.dwCurrentState =
      SERVICE_START_PENDING;
   ServiceStatus.dwControlsAccepted =
      SERVICE_ACCEPT_STOP |
      SERVICE_ACCEPT_SHUTDOWN | SERVICE_ACCEPT_NETBINDCHANGE;
   ServiceStatus.dwWin32ExitCode = 0;
   ServiceStatus.dwServiceSpecificExitCode = 0;
   ServiceStatus.dwCheckPoint = 0;
   ServiceStatus.dwWaitHint = 0;
}
I am really puzzled about the privilege.(SERVICE_ALL_ACCESS do not have the
privilege?)
In fact I even can not start my service when using CreateService.
I only want the NetQueryDisplayInformation working .

"Bruno van Dooren [MVP VC++]" <bruno_nos_pam_van_dooren@hotmail.com> ????????????:eq6ad6QSHHA.3440@TK2MSFTNGP03.phx.gbl...

res = NetQueryDisplayInformation(szServer, 1, i, 1000, 0xFFFFFFFF,
&dwRec, (void **)&pBuff);
it's OK in exe
but failed in a service

return ERROR_ACCESS_DENIED,
why?


Because your service is running with different credentials.
Probably with LOCAL_SYSTEM credentials. This means it cannot access
network resources.
Try to change the logon configuration for your service to a named user
account that has access to szServer. That should help.

--

Kind regards,
   Bruno van Dooren
   bruno_nos_pam_van_dooren@hotmail.com
   Remove only "_nos_pam"

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