Re: Rounding of the double

Hi Alex,

I still think you can do what you want using DWORDs and just assume the
decimal position rather than using floats of doubles. FWIW, I think you're
going to have the same problem in any language as the floating point
technology is not specific to C++ or unmanaged C++. There are places where
users have worked around it.

For example, I wrote this function years ago and still use it for finance
applications where I want to show dollars and cents. It seems to still
work. It's not fancy and I certainly wouldn't use it for anything time
critical. Of course I also wanted to round off to the nearest significant
digit as well.

Tom

double round(double value, int sig) /* Round a double or float to 'sig'
places to the left or right of the decimal. */
{
    double dhold;
    long ihold;

    if (sig > 0) { /* Round to the right of the decimal place */
        dhold=(value+(5/pow(10.0,(double)sig+1)))*pow(10.0,(double)sig);
        ihold=dhold;
        return((double)ihold/pow(10.0,(double)sig));
    }
    else { /* Round to the left of the decimal place */
        sig=abs(sig);
        dhold=(value+(5*pow(10.0,(double)sig-1)))/pow(10.0,(double)sig);
        ihold=dhold;
        return((double)ihold*pow(10.0,(double)sig));
    }
}

"Alex" <alsim123@hotmail.com> wrote in message
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