Re: CreateProcess command line

From:

"David Ching" <dc@remove-this.dcsoft.com>

Newsgroups:

microsoft.public.vc.mfc

Date:

Tue, 12 Aug 2008 20:01:23 -0700

Message-ID:

<78sok.19876$uE5.8857@flpi144.ffdc.sbc.com>

"Tony" <lazy.herbert@homeandresting.com> wrote in message
news:eT9AZL08IHA.4468@TK2MSFTNGP06.phx.gbl...

Hi,

I'm trying to recreate a straight forward command line call to initialise
a SQL Express installation.

The path I need to pass, including parameters, is as follows

"sqlexpr32\\setup /qb /settings sqlexpr32\\template.ini" and my call to
CreateProcess is as follows

CreateProcess( NULL, // app name
                       tcCmdLine, // command line
                       NULL, NULL, // process security, thread security
                       FALSE, // inherit handles
                       CREATE_DEFAULT_ERROR_MODE, // flags
                       NULL, // environment block
                       NULL, // current directory name
                       &si, // pointer to startup info struct
                       &pi ); // pointer to process information struct

but I get a failure due to the settings file.

The reason I am posting here is because the same string works just fine
from the command line. The only difference being that prior to the
sqlexpr32 is the path, e.g. "C:\sqlexpr32\setup.exe /qb /settings
C:\sqlexpr32\template.ini"

Any possible thoughts on what may be wrong would be much appreciated.

Perhaps the problem is the command-line parameters are getting mixed up with
the file name. Try setting the first parameter, app name to:

    "C:\sqlexpr32\setup.exe "

and setting the second parameter, command line, to

  "/qb /settings C:\sqlexpr32\template.ini"

Also, you may need to set the 3rd from last parameter, current directory, to

  "C:\sqlexpr32", if setup.exe assumes that the folder it is in is the
current one.

-- David