Re: a callback function across the dll boundary

From:
"Doug Harrison [MVP]" <dsh@mvps.org>
Newsgroups:
microsoft.public.vc.mfc
Date:
Sun, 25 Jun 2006 21:22:25 -0500
Message-ID:
<vm2q92pbvj0fjk9hk1epeu68etn9qg88mr@4ax.com>
On Sat, 24 Jun 2006 07:08:33 GMT, "Tony Young" <jdt_young@yahoo.com> wrote:

Hello Doug,

Thank you very much for the help. One thing I don't understand is why you
changed CallBackFunc(int nRet) from a class member function to a static (or
global) function.


I changed it to a static member function so that it would be compatible
with the function pointer type you went on to use:

typedef void(*funcptr)(int);


The corresponding non-static member function typedef would have been
written like this:

typedef void(CMain::*funcptr)(int);


Is it a must?


For the typedef you defined, yes.

There's a big difference between a "pointer to member function" (the
non-static quality is implied by the term) and a normal function pointer.
An instance of an object is required to call a non-static member, and you
need an object instance to call a pointer to member function. Calling a
global function or a static member function does not involve an object
instance, and both can be represented by a normal function pointer, which
is what you used. You could use a pointer to member, but then you'd have to
keep a pointer to an object through which you'd invoke the callback.

If I create variable m into heap (by the
following statement) instead, and make m outlive m_pSupport, then it's safe
to make CallBackFunc(int nRet) as a member function. Is it right?

CMain *m;
...
m = new CMain;

Your further help is much appreciated.


If you're going to refer to an object, the object has to exist when you
refer to it. If the callback is a pointer to member function, you need a
valid object on which to call it.

--
Doug Harrison
Visual C++ MVP

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