Re: overriding global operator new/delete
 
"Tom Widmer [VC++ MVP]" <tom_usenet@hotmail.com> wrote in message 
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Ben Voigt wrote:
"Tom Widmer [VC++ MVP]" <tom_usenet@hotmail.com> wrote in message 
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Alexander wrote:
Hi!
I have implemented a memory manager and I would like to override the 
global operators new and delete. My application is a bunch of dll's 
where some are loaded at run-time and some are linked to during compile 
time. My memory manager organized in a dll. Naturally, compilation 
process generates memsub.dll and memsub.lib which I link to the 
application before msvcrt by placing the memsub.lib before any of 
standard libraries in the linker command line. However, there is no 
call to memsub's new/delete operators. Then I tried to export the 
operators new/delete from memsub.dll by using __declspec(dllexport) and 
I received following compiler errors:
[snip]
I work with VC 6.
Could you please explain to me this a behavior or maybe you could
tell me what I'm doing wrong for global operator new/delete 
replacement.
Each module gets its own operator new and delete. operator new has a 
fixed signature (it is declared in <new>), so you can't change that 
signature by declaring it __declspec(dllim/export).
So I think you'll have to override new and delete separately for each 
module (exe and dll) in your application that you want to use the memory
It should be possible to accomplish this with a static library.  Can the 
OP possibly somehow combine these functions with the import library to 
create a single static library, or are object code libraries and import 
libraries necessarily distinct?
Yes, a static library would work fine I think, with the static library 
containing the implementations of operators new and delete. Linking each 
module (except the DLL containing the memory manager!) with this static 
library would be sufficient I think.
What I was wondering was, is it possible to merge the .obj file with said 
implementations with the DLL import library, so that there's only one .lib 
file to link with?
Tom 
  
  
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