Re: Creating DLL Entry Point

From:

"Mark Salsbery [MVP]" <MarkSalsbery[MVP]@newsgroup.nospam>

Newsgroups:

microsoft.public.vc.language

Date:

Wed, 5 Sep 2007 11:30:05 -0700

Message-ID:

<elTFMr#7HHA.1204@TK2MSFTNGP03.phx.gbl>

Does rundll32.exe call DllMain() by default? If so, is the reason ==
DLL_PROCESS_ATTACH?
I don't think so.

My understanding of rundll32.exe is that it's for use with DLLs that have a
specific entry point which is specified on its command line. The entry
point function is defined something like:

extern "C" __declspec(dllexport) void CALLBACK FunName(HWND hwnd, HINSTANCE
hInstance, LPTSTR lpCmdLine, int nCmdShow)
{
....
}

and the rundll32 command line is

rundll32.exe dllname.dll,FuncName [arguments]

Mark

--
Mark Salsbery
Microsoft MVP - Visual C++

"FFrozTT" <tech@millennium.ab.ca> wrote in message
news:1189012808.418625.213520@y42g2000hsy.googlegroups.com...

I have a small project that works fine as an EXE. Now I want to make
it into a DLL. I've created a DllMain routine and set it as the
entry
point (code below). Then from DllMain I try to initialize my main
routine called ThreadProc. I've tryed this several different ways
and
can't get it to work. It compiles fine but when I go rundll32
mydll.dll nothing happenes (works in exe form.)

BOOL APIENTRY DllMain(HMODULE hModule, DWORD ul_reason_for_call,
LPVOID lpReserved)
{
       if (ul_reason_for_call == DLL_PROCESS_ATTACH)
       {
               HANDLE hThread = CreateThread(NULL,0,&ThreadProc,NULL,
0,NULL);
               CloseHandle(hThread);
       }

   return TRUE;

}

Any assistance would be greatly appreciated.