Re: exception from C function?

From:

"Ben Voigt [C++ MVP]" <rbv@nospam.nospam>

Newsgroups:

microsoft.public.vc.language

Date:

Wed, 30 Jan 2008 08:46:54 -0600

Message-ID:

<uua8#60YIHA.5160@TK2MSFTNGP05.phx.gbl>

"George" <George@discussions.microsoft.com> wrote in message
news:9A40A513-E943-40D9-81B7-99A2EE049DB1@microsoft.com...

Hi Tim,

No. jmp changes the flow of the code. It doesn't affect the stack.
Exception unwinding is more complicated than this.

I understand unwinding is more complex. But we are talking about exception
thrown from C++ to C. I think there is no exception registration entry in
C
qsort, and what I mean is the major work is jump to higher address space
to
look for exception handler. When you jump to higher address to look for
exception handler, current lower address stack will be disgarded -- this
is
how stack object on C function qsort is freed automatically.

The C++ exception logic provided by the compiler does adjust the stack
pointer. This is done by a write to the EBP and ESP registers, not a jmp
instruction.

If I missed anything important, please feel free to correct me. :-)

regards,
George

"Tim Roberts" wrote:

George <George@discussions.microsoft.com> wrote:

memory on the stack. Local POD-style stack variables will be freed
gracefully even if an exception happens.

I assume it is implemented by a simple jmp assembly command to a higher
memory address? Right?

No. jmp changes the flow of the code. It doesn't affect the stack.
Exception unwinding is more complicated than this.

2.

Any comments about why modern C++ library implements qsort in C, why not
in
C++?

Because it is ridiculous to rewrite something that doesn't need
rewriting.
The qsort routine in C run-time libraries is well-established,
well-tested,
and well-optimized. The C++ run-time library needs EXACTLY the same
routine, with EXACTLY the same parameters and EXACTLY the same semantics.
Why on earth wouldn't you use EXACTLY the same code?

(you see, almost all the libraries -- like STL algorithms -- are C++,
why
leaving qsort as a legacy C function?)

It's just not true. STL is C++, because it needs templates, but "almost
all the libraries" is just not true.
--
Tim Roberts, timr@probo.com
Providenza & Boekelheide, Inc.