RE: Passing a variable to a member class
This will work:
class A
{
ToolClass myTool;
B myB;
public:
class A ()
: myTool (),
myB (&myTool)
{
}
};
However, I'd like to add that this is very poor design as it defeats some of
the principles of OOP. Perhaps it makes more sense to derive B from
ToolClass? (ie. use inheritance)
HTH
Brian
"Zapanaz" wrote:
This seems like a stupid question ... it's fairly basic but I am not
seeing it.
I have a class, class A, which has a member, a second class, call it
ToolClass.
Class A also has a member which is an instance of class B.
So I have
class A
{
ToolClass myTool;
B myB;
}
Now I have class B, which needs to have a pointer to the same instance
of ToolClass as class A, it's important that they be the same
instance. Class B needs this when it is instantiating.
class B
{
ToolClass * myTool;
}
So class A instantiates, the constructor for ToolClass is called to
create A.myTool, then the default constructor for class B is called.
(I could set the pointer into myB.myTool in the constructor of A, but
the constructor of B is already called before execution actually
enters the constructor of A).
I can add a constructor to B that allows me to pass in &myTool ... it
seems like that ought to be simple, but I am not seeing how to do it.
I declare the member object in class A, myB, which is of class B.
This causes the default constructor of class B to be called, which
doesn't have a pointer to myTool, which it needs during it's
constructor execution.
I could make the default constructor something like B(ToolClass *
myTool=NULL), but that doesn't really help.
So am I missing something obvious? It seems like there has to be a
way to do this ... or maybe not, maybe that's forbidden because I
can't necessarily depend on the ToolClass object being constructed
before myB.
--
Joe Cosby
http://joecosby.com/
HellPope Pinata:
beat me with a stick, I'm full of candy
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