Re: Hidden overloaded operator in multiple inheritance

From:
"Alex Blekhman" <tkfx.REMOVE@yahoo.com>
Newsgroups:
microsoft.public.vc.language
Date:
Fri, 12 Oct 2007 19:17:17 +0200
Message-ID:
<O7LZ7OPDIHA.5136@TK2MSFTNGP03.phx.gbl>
"Alex Blekhman" wrote:

[...] The same behaviour can be demonstrated with
following simple example:

class A
{
public:
   int operator+(int) { return 42; }
};

class B
{
public:
   double operator+(double) { return 3.14; }
};

class C : public A, public B
{
};

int main()
{
   C c1;
   int i = 5;
   double d = 10.5;

   c1 + i; // Error!
   c1 + d; // Error!

   return 0;
}


I applied SP1 for my VC++ 2005 Pro and tweaked the above
code a little bit. First of all, the code with templates
from OP still doesn't compile with the same errors as before
application of SP1.

Second, I think that VC++ actually does have a bug in call
resolving mechanism. The function name from left base class
`A' actually hides the name from right base class `B'
instead of competing with it for inclusion in name lookup
set. The above code compiles with warning that double is
implicitly converted to int. So, obviously `int A::operator+
(int)' kicked in. If I replace double in class' B `operator
+' with `char*', for example, then I get C2679 ("no
appropriate operator found").

Comeau compiler correctly reports ambiguity error in any
case (double or char*).

Alex

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