View contents of an array!

Hello,

Sorry for the stupid questions I am asking today!

In the following program, if I put a breakpoint at the following line:

s++; //<<< break point here

How can I view the contaents stored in the following array:

int r[10];

It seems that I can see the contents while on the break point. This is
annoying since I would like to see if the values are actually being written
to this array!

=============================Heres the program!
#include <stdio.h>
//#include <iostream>
//#include <math.h>
//using namespace std;

int w[] = {100,101,102,103,104,105,106,107,108,109}; //Write to file
int r[10]; //={100,101,102,103,104,105,106,107,108,109}; //Read from file

void main(void)
{
FILE *fp;
int x,s;
int Stop;

// Open file for writting
if((fp = fopen("Rougefile", "wb")) == NULL){
        printf("Cannot open file. \n");
        cin >> x;
        exit(1);
}

//Write to file
for(s=0;s<10;s++)
{
    if(fwrite(&w[s],1,1, fp) != 1) {
        printf("Write error occured. \n");
        cin >> x;
        exit(1);
    }
}

fclose(fp);

//Open file for reading
if((fp = fopen("Rougefile", "rb")) == NULL){
        printf("Cannot open file. \n");
        cin >> x;
        exit(1);
}

//Read from file
for(s=0;s<10;s++)
{
    if(fread(&r[s],1,1, fp) != 1) {
        printf("Read error occured. \n");
        cin >> x;
        exit(1);
    }
}

s++; //<<<< Breakpoint here!

for(s=0;s<10;s++)
{printf("Here is the file's data > %d", r[s]);}

cin >> x;
//cin >> Stop;

}
=======================================

--
Best regards
Robert