Re: template function issue

From:
=?Utf-8?B?R2Vvcmdl?= <George@discussions.microsoft.com>
Newsgroups:
microsoft.public.vc.language
Date:
Wed, 12 Dec 2007 23:16:00 -0800
Message-ID:
<01D18960-0132-464A-890E-2FA08DE8E37C@microsoft.com>
Thanks for your clarification, Tim!

But, to pass an array is ok in C++. Can you try the following code please?

#include <iostream>

using namespace std;

void Foo1 (char input[12])
{
    std::cout << typeid(input).name() << endl; // output char*

    input [0] = '1';

    return;
}

void Foo2 (char (&input) [12])
{
    std::cout << typeid(input).name() << endl; // output char [12]

    input [0] = '2';

    return;
}

void Foo3 (char* input)
{
    input [0] = '3';

    return;
}

int main()
{
    char buf[] = "Hello World";

    Foo1 (buf);

    cout << buf << endl; //output "1ello World"

    Foo2 (buf);

    cout << buf << endl; //output "2ello World"

    Foo3 (buf);

    cout << buf << endl; //output "3ello World"

    return 0;
}

regards,
George

"Tim Roberts" wrote:

George <George@discussions.microsoft.com> wrote:

Why GetArrayLength(const T(&arr)[size]) works, but

GetArrayLength(const T(arr)[size]) -- I removed & does not work?


Ulrich already answered that question. You can't pass an array to a
function. You can pass is the address of an array, either by reference or
by pointer.
--
Tim Roberts, timr@probo.com
Providenza & Boekelheide, Inc.

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