Re: life cycle of exception object

From:
=?Utf-8?B?R2Vvcmdl?= <George@discussions.microsoft.com>
Newsgroups:
microsoft.public.vc.language
Date:
Mon, 4 Feb 2008 05:45:01 -0800
Message-ID:
<A6F080CC-8A65-4B07-AD13-E9BC23E85286@microsoft.com>
Thanks Igor,

1.

an address of a local variable there: you just end up with a dangling
pointer as soon as catch clause finishes.


The term "dangling" means the pointer is pointed to undefined data?

2.

I have made some further study and prove that the exception object instance
in catch block and in try block are different -- there will be a copy. But I
am not 100% sure whether in all situations compiler will make a copy of
original exception object instance. Any comments?

Here is my code.

#include <iostream>

using namespace std;

class Foo {
public:
    Foo(int input)
    {
        this->a = input;
        cout << this << endl;
    }

    Foo (const Foo& input)
    {
        this->a = input.a;
        cout << this << endl;
    }
    int a;
};

void foo()
{
    try {
        Foo* f = new Foo (100);
        throw *f;
    } catch (const Foo& e)
    {
        cout << e.a << endl;
    }
}

int main()
{
    foo();
}

regards,
George

"Igor Tandetnik" wrote:

"George" <George@discussions.microsoft.com> wrote in message
news:0025B68B-A6F2-47E2-8504-42A72DC4DD65@microsoft.com

I am wondering what is the life cycle of the exception object which
reference variable e binded to?


It's guaranteed to exist through the catch clause, but no longer (unless
rethrown, but even then the compiler may choose to make a copy and
destroy the original).

For example, could we bind a global
reference to the exception object referred by e?


Show me the code where you do that. There's simply no syntax for that.

You could take an address of the exeption object, and store it in a
global pointer variable. This would be no different than, say, storing
an address of a local variable there: you just end up with a dangling
pointer as soon as catch clause finishes.

The life cycle of variable e itself should not beyond the bracket,
right?


Right. Except that you probably mean lifetime when you say "life cycle".
--
With best wishes,
    Igor Tandetnik

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necessarily a good idea. It is hard to be sure where they are going to
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