Re: C2664 on initializing auto_ptr with const patam in constructor
David Wilkinson wrote:
Fabian wrote:
Hello,
I've got a class like this:
namespace Spimaging
{
class SPIMAGING_API StackOpZDivision: public IStackOperation
{
private:
const auto_ptr<Spimage> m_opDivisor;
public:
explicit StackOpZDivision(const Spimage* i_opDivisor);
...
};
StackOpZDivision::StackOpZDivision(const Spimage* i_opDivisor):
m_opDivisor(i_opDivisor) {}
}
When I try to compile it I get the message "error C2664:
'std::auto_ptr<_Ty>::auto_ptr(_Ty *) throw()' : cannot convert
parameter 1 from 'const Spimaging::Spimage *' to 'Spimaging::Spimage *'"
I'm just trying to initialize a const auto_ptr with a const value. Is
that impossible?
Fabian:
The auto_ptr constructor does not take a const pointer argument. The
const-ness of the auto_ptr will prevent you from calling non-const
methods of Spimage.
Fabian:
Oops, I forgot to tell you that when I tested this, I used auto_ptr<const Spimage>.
Why do you think you want the auto_ptr itself to be constant?
--
David Wilkinson
Visual C++ MVP
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