Re: msvc++ 2005 template question

From:
"Carl Daniel [VC++ MVP]" <cpdaniel_remove_this_and_nospam@mvps.org.nospam>
Newsgroups:
microsoft.public.vc.language
Date:
Wed, 18 Oct 2006 08:26:22 -0700
Message-ID:
<urZ6Fns8GHA.4632@TK2MSFTNGP02.phx.gbl>
olli wrote:

I have a library which I want to build on msvc++ 2005. however the
compiler generates the following warnings and errors concerning the
following source snippet:

template <class EOT>
class eoSelectivePopulator : public eoPopulator<EOT>
{
public :

    using eoPopulator< EOT >::src;

    eoSelectivePopulator(const eoPop<EOT>& _pop, eoPop<EOT>& _dest,
eoSelectOne<EOT>& _sel)
        : eoPopulator<EOT>(_pop, _dest), sel(_sel)
        { sel.setup(_pop); };

    /** the select method actually selects one guy from the src pop */
    const EOT& select() {
        return sel(src);
    }

private:

    eoSelectOne<EOT>& sel;
};

---

output is:

eopopulator.h(192) : warning C4346: 'EOT::Fitness' : dependent name is
not a type
prefix with 'typename' to indicate a type


The code you've shown is not the source of this error (clearly, since
there's no mention of EOT::Fitness in this code).

I'm going to assume that this is code you're porting from VC7 (2002) or
earlier. The issue here is that, as the error message explains, a dependent
name is not a type name. So what's a dependent name? Roughly speaking,
it's a name whose definition depends on one or more template parameters. In
this case, EOT::Fitness is a dependent name.

Early C++ compilers, like VC6 and VC7 would accept such names as being type
names, but that causes problems with other constructs where the name isn't
really a type. So, the C++ standard mandates that a dependent name is never
a type name unless you explicitly state that it is. The way you do that is
by using the 'typename' keyword.

Generally, you solve this error (and make your code standard complaint) by
simply adding the typename keyword before the name, so replace
"EOT::Fitness" with "typename EOT::Fitness".

-cd

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