"Tom Widmer [VC++ MVP]" <tom_usenet@hotmail.com> schrieb im Newsbeitrag
news:%23tlRhSWjHHA.4772@TK2MSFTNGP05.phx.gbl...
You have your answer, but just to make things worse, what you are doing is
illegal anyway - you aren't allowed to specialize std function templates
unless the specialization involves a user-declared name (e.g. you can
specialize them for your own types, but not for built-in or standard
library types).
In practice, whether you care about this is up to you, but it is possible
a library might include its own explicit specializations or explicit
instantiations for such specializations, thus rendering your own explicit
specialization either undefined behaviour or a compiler error.
But what if I want to specialize a template function that I wrote myself? I
might have template function such as:
template <class T> inline
const T& minimum( const T& a, const T& b )
{ return a < b ? a : b; }
Then how do I specialize it in such a way that I can pass C-style strings?
Specialize it for both char* and char const*.
guess the answer is to overload the function instead of specializing it...
Or explicitly specialize for all types desired.