Re: Explicitly specializing std::min() on VC++ 2005 Express Edition

From:
"Tom Widmer [VC++ MVP]" <tom_usenet@hotmail.com>
Newsgroups:
microsoft.public.vc.language
Date:
Fri, 04 May 2007 12:47:52 +0100
Message-ID:
<eyKHNIkjHHA.4872@TK2MSFTNGP03.phx.gbl>
Matthias Hofmann wrote:

"Tom Widmer [VC++ MVP]" <tom_usenet@hotmail.com> schrieb im Newsbeitrag
news:ux2I2YajHHA.4516@TK2MSFTNGP03.phx.gbl...

Ahh, of course that won't work for arrays of char. For your template
above, you'd need to do this:

template <class T>
struct min_impl
{
  static const T& impl(const T& a, const T& b)
  { return a < b ? a : b; }
};

template <class T> inline
const T& minimum( const T& a, const T& b )
{ return min_impl<T>::impl(a, b); }

Then you can specialize min_impl for char arrays:

template <std::size_t N>
struct min_impl<char[N]>;


This specialization for non-const char[N] seems superflous, as minimum<T>()
accepts a constant reference, so min_impl<T>::impl() will never see a
non-const char[N].


Good point, though I think it's the other way around - char[N] is
needed, but not char const[N].

template <std::size_t N>
struct min_impl<char const[N]>;


What does the definition of this specialization of min_impl look like?


template <std::size_t N>
struct min_impl<char[N]>
{
  static char const (&impl(char const (&a)[N], char const (&b)[N]))[N]
   { return std::strcmp(a, b) < 0 ? a : b; }
};

C++ declaration syntax isn't very nice.

There's an additional problem, that the function doesn't allow comparing
arrays of different length. That's a bit trickier to handle though!

Tom

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